Two Consecutive Angles Of A Parallelogram Have Measure (X+30)\Xb0 And \Xb2(X+30)\Xb0.What Is The Measure Of The Smaller Angle?

two consecutive angles of a parallelogram have measure (x+30)° and ²(x+30)°.what is the measure of the smaller angle?

Answer:(×+30) and 2 (×-30)

(×+30) + 2 (×-30)

=180 ×+30+2×-60-180

3×-30=180 3×=210

×=70

-70+30=100

angle B=2 (70-30)

= 80 smaller angle

Step-by-step explanation:


Comments

Popular posts from this blog

Sino Si Juanito Pelaez Ng El Filibusterismo

Criticize Your Own Beliefs......, My Belief In "Don\T Wait For An Apology To Forgive"..., So The Thing Is I Want You To Criticize My Belief....