Two Consecutive Angles Of A Parallelogram Have Measure (X+30)\Xb0 And \Xb2(X+30)\Xb0.What Is The Measure Of The Smaller Angle?

two consecutive angles of a parallelogram have measure (x+30)° and ²(x+30)°.what is the measure of the smaller angle?

 

Answer:(×+30) and 2 (×-30)

(×+30) + 2 (×-30)

=180 ×+30+2×-60-180

3×-30=180 3×=210

×=70

-70+30=100

angle B=2 (70-30)

= 80 smaller angle

Step-by-step explanation: